Lithium-iodine battery can be used as the power supply of cardiac pacemaker. The battery reaction is: 2li (s)+I2 (s) ═ 2li i (s) △ h "0 known: 4li(s)+O2 (

A.4li (s)+O2 (g) ═ 2li2o (s) △ h1=-32kj? Mol-1①, 4lii (s)+O2 (g) ═ 2i2 (s)+2li2o (s) △ H2 =-114kj? Mol- 1②, put Equation ①? ②2 Get 2Li(s)+I2(s)= 2LiI(s)△H =? 324kJ/mol？ (? 114kj/mol) 2 =-105kj/mol, so a is correct;

B. The reaction formula of the electrode on the anode of the primary battery is I2+2e-=2I-, so B is wrong;

C. When there is 14gLi consumption, theoretically, the amount of substances that release electrons is =14g7g/mol×1= 2mol, so c is correct;

D. When a chemical reaction occurs, it follows the law of conservation of mass before and after the reaction, and these substances are all solids, so the mass remains unchanged, so D is correct;

So choose B.