Traditional Culture Encyclopedia - Almanac inquiry - In an ordinary calendar, can the sum of three dates in the same column of three adjacent rows be 30? If so, what are these three numbers?
In an ordinary calendar, can the sum of three dates in the same column of three adjacent rows be 30? If so, what are these three numbers?
In an ordinary calendar, three dates in three adjacent rows in the same column are arithmetic progression, with a difference of 7.
If the sum can be 30, the intermediate date must be 30/3= 10.
It can be inferred that the three numbers are 3 10 17 respectively.
Can the sum of these three numbers be 8 1? Then the middle day is 8 1/3=27.
It can be calculated that the three numbers 20 27 34 34 do not exist outside the date range.
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