What is the calculation formula of cylinder thrust?

Bottom area of cylinder inner diameter × system pressure = output force-n.

For example, the cylinder diameter is 40, and the system pressure is 0.5MPA.

20×20×π×0.5 = 628 Newton.

The thrust force on the cylinder piston rod f 1 =π/4×D2×p×? (noun)

The pulling force on the piston rod of the cylinder F2=π/4×(D2-d2)×P×? (noun)

F 1: the thrust when the piston rod is pushed out.

F2: the pulling force when the piston rod is pulled back.

D: Internal diameter of cylinder (piston diameter).

D: the diameter of the piston rod.

P: air source pressure.

: Load rate (at low speed? = About 65% faster? = about 30%).

Related content explanation:

The output force of the cylinder has nothing to do with the stroke length, for example:

The air pressure is 0.5 MPa (5.0985811kgf/cm).

The diameter of the cylinder is 50 mm (5 cm).

Cross-sectional area of cylinder = 3.14x (5/2) 2 =19.63 (square centimeter).

Therefore, the theoretical output at 0.5Mpa = 5.0985811*19.63 =100.085 (kg force) can also be directly referred to the following cylinder output table.

However, it is only a theoretical contribution, and it will be quick to look up the table according to the actual working conditions.