YHYA throttle

(1) methane contains two elements: carbon and hydrogen. The products of combustion are carbon dioxide and water. Hydrogen consists only of hydrogen. The combustion product is water, carbon monoxide contains carbon and oxygen, and the combustion product is carbon dioxide. There are no water droplets on the inner wall of the beaker above the flame 2, which means that no water is generated, but carbon monoxide is generated. Water drops appear on the inner wall of beaker above flames B and C, and the limewater in glass B becomes turbid, indicating that glass B is methane, while there are water drops on the inner wall of glass C, and the injected clarified limewater has not changed, indicating that only water is generated, but hydrogen.

So the answer is: carbon monoxide; Methane; Hydrogen.

(y) The combustion of carbon monoxide produces carbon dioxide, and the reaction equation is YCO+OY &；; Nb gets p; Light Nb gets p; . & nb gets p; The combustion of yCOy methane produces carbon dioxide and water, and the reaction equation is CH4+yoy &；; Nb gets p; Light Nb gets p; . & nb gets p; COy+yHyO； Hydrogen burns to produce water, and the reaction equation is yhy+oy &；; Nb gets p; Light Nb gets p; . & nb gets p; YHyO carbon dioxide reacts with clear limewater to generate calcium carbonate and water COY+C2 (OH) Y ═ C2CO3 ↓+HYO.

So, the answer is: yco+oy &；; Nb gets p; Light Nb gets p; . & nb gets p; YCOyCH4+ year-on-year & nb gets P; Light Nb gets p; . & nb gets p; COy+yHyO； yHy+Oy & amp； Nb gets p; Light Nb gets p; . & nb gets p; yHyOCOy+C2(OH)y═C2CO3↓+HyO.

(3) Solution: Suppose the mass is 1g, the mass of oxygen that reacts with hydrogen is X, the mass of oxygen that reacts with methane is Y, and the mass of oxygen that reacts with carbon monoxide is Z..

yHy+Oy & amp； Nb gets p; Light Nb gets p; . & nb gets p; yHyO

4 3y

1 g x

4 1g

Mouth: x=8g

CH4+ year-on-year & nb gets P; Light Nb gets p; . & nb gets p; COy+yHyO

16。 Nb gets p; 64

1g & amp； Nb gets p; & nb gets p; y

16 1g

y=4g

yCO+Oy & amp； Nb gets p; Light Nb gets p; . & nb gets p; yCOy

r6 3y

1g & amp； Nb gets p; z

rg 1g

z=0.r7g

Through calculation and comparison, it can be seen that the oxygen mass required for complete combustion of Hy, CH4 and CO is the most, and carbon monoxide is the least.

So the answer is: hydrogen.