How does geography calculate the direct dimension of the sun by using the formula of noon sun height angle?

To solve the problem of solar panel tilt by using noon solar height, we should pay attention to two points: the formula of noon solar height angle: h = 90-| local latitude |. (If the local latitude is in the same hemisphere as the latitude of the sun's direct point, use a minus sign, otherwise use a plus sign, abbreviated as the same minus but different plus) In order to make full use of solar energy, solar panels are often perpendicular to the sun. That is to say, the inclination angle (∠ θ) of the solar panel in the above picture is complementary to the noon sun height angle (h). Further summary ∠ θ+90-| local latitude | = 90. That is, ∠ θ = | local latitude+latitude of direct solar point |. This little conclusion is best remembered, and it is very convenient to apply in the future! It will be easy to look at the problem again. Find the inclination angle of the solar panel for the option: Option A: The Arctic Circle is full of extreme days, indicating that the solar term is the summer solstice, and the latitude of the direct point of the sun is 23 26 ′ n; Then ∠ θ = 40 N-23 26 ′ N =17 34 ′ b Option: The Arctic Circle is full of polar nights, indicating that the solar term is from winter to the sun, and the latitude of the direct point of the sun is 23 26 ′ s; Then ∠ θ = ∠θ= 40° N+23° 26'N = 63° 26'C ′ C Option: the solar terms are halved, and the latitude of the direct point of the sun is 0; Then ∠ θ = 40 N-0 = 40 D option: the solar term is still divided into two parts, the same as option C, so ∠θ = 40. To sum up, the unreasonable option is D.