Python judges the current solar terms

# leap year formula, four years is leap year, one hundred years is not leap year, and four hundred years is leap year.

Year = Enter ("Please Enter Year")

Month = input(" "# Pay attention to the month, but it's a month now, not a few months later.

Day =7

Def judge _ leap year (year):

If (year %4==0, year% 100! =0 ):

Return 1

elif(year%400==0):

Return to 2

Otherwise:

Return 0

Year _ day = [3 1，28，3 1，30，3 1，30，3 1，30，3 1]

Leap _ year = [3 1，29，3 1，30，3 1，30，3 1，30，3 1。

Leap _ year _ f = [3 1，30，3 1，30，3 1，30，3 1，3 1，30，365438。

Year_rule=[year_day, leap year, leap year f]

Count_day=0 # Initialization days are 0.

For I (month-1) in the range: # Pay attention to the month, but what month is it now, not several months have passed.

Count _ day+= year _ rule[judge _ leap year (year) ][i]

Print (Counting Days)

Counting Day+= Day

Print ('Today is the first day of this year', count_day,' day')