(20 1 1? Jiaozuo simulation) roll the rectangular iron sheet as shown in the figure into a cylinder, and make it into a container with a suitable bottom. container

=4÷2,

=2 (cm);

3. 14×22×6.28,

=3. 14×4×6.28,

=78.8768 (cubic centimeter);

②6.28÷3. 14÷2,

=2÷2,

= 1 (cm);

3. 14× 12× 12.56,

=3. 14× 1× 12.56,

=39.4384 (cubic centimeter);

Because 78.8768 cubic centimeters > 39.4384 cubic centimeters;

So the maximum volume of this container is 78.8768 ml.

The maximum capacity of this container is 78.8768 ml.

So the answer is: 78.8768.