How to find the derivative of y = 1/x?

According to the derivative formula (x n)' = NX (n-1) (n ∈ q *), one tenth of x is-1power of x, so the derivative of one tenth of x is one tenth of the square of negative X.

Commonly used derivative formula:

C'=0(C is a constant function)

x^n)'= nx^(n- 1) (n∈Q*)

(sinx)' = cosx

(cosx)' = - sinx

(e^x)' = e^x

(a x)' = (a x) lna (ln is a natural logarithm)

(Inx)' = 1/x(ln is natural logarithm)

(logax)' =x^(- 1)/lna(a & gt； 0 and a is not equal to 1)

(x^ 1/2)'=[2(x^ 1/2)]^(- 1)

( 1/x)'=-x^(-2)