Xiaoyangjia traditional customs

Solution: Solution: Colored lights are connected in series, and the equivalent circuit diagram is as follows:

(1) the total voltage connected to the household circuit is U=220V, and the filament resistance R0 of each colored lamp,

From I=UR: R0=U forehead I forehead = 8V0.5A = 16ω,

The voltage across each lamp is:

U0=U33=220V33=203V，

The electric power of each lantern is P0 = U20R0 = (203V) 216ω ≈ 2.78W; ?

(2) When the filament of the lantern is broken and the circuit is open, the power supply voltage is applied to the lantern, and the voltage at both ends of the lantern is 220 V;

(3) When a colored lamp goes out, the whole circuit consists of 32 colored lamps and a section of metal wire connected in series.

The total resistance is R=32R0+R line = 32× 16ω+ 10ω= 522ω.

Total current is I' = ur = 220v522ω =110260a,

The electric power of each lamp is

P0′= I′2？ r0 =( 1 10260 a)2× 16ω≈2.84 w；

(4) Assume that when the filaments of N color lamps are disconnected, the total current is equal to 0.5A

Total resistance r ′ = (33-n) r0+NR line =33R0-n(R0-R line)?

Total current I "= ur' = 220v33r0? n(R0？ R line) = 220v33x16ω? n( 16ω？ 10ω)= 0.5A；

Solution: n≈ 14.67,

∴ 15 lamp filament is broken, and the current of the whole string of lamps will exceed 0.5A 。

Answer: (1) When each lamp emits light, the electric power consumed by each lamp is 2.78 W；;

(2) When the filament of a lamp is broken, the voltage across the lamp is 220 V;

(3) After this lamp line is connected to the circuit, other colored lights can emit light, and the electric power consumed by each lamp is 2.84 W；;

(4) The filament of 15 of this string of small colored lights is broken, and the current of the whole string of lights will exceed 0.5A 。