Project management and practice of second-level constructor (case 6)

Case 6 Plastering and ground engineering of the second floor are divided into two construction processes: roofing and wall plastering, and paving stones on the ground. Plastering is divided into three layers, each layer of plastering work lasts for 32 days. The stone laying time is 16 days, and the building is divided into four flow sections to organize the construction. (Exam sophomore builder)

Question:

(1) What is irregular flow construction? What are its flow parameters?

(2) Briefly describe the main process of organizing flow construction.

(3) What is the working time? What is the running water beat? If the resource supply can meet the requirements, please organize the construction according to the double-beat flow construction method and determine the construction period.

Case 6 answer

(1) Different-rhythm flow construction: the flow beats of each operation team in the flow group are equal, but the flow beats of different operation teams are not necessarily equal.

Flow parameters include time parameters, space parameters and process parameters.

(2) Organize the main working procedures of flowing water construction:

Dividing the construction process → dividing the construction section → organizing the construction team, determining the running rhythm → ZuoYeDui's continuous operation → The work of each ZuoYeDui should overlap appropriately.

(3) Work duration: the time from the start to the completion of a job.

Flow rhythm: the time for a construction team to complete all the work in a construction section.

Organize the construction according to the multi-beat flow construction method;

Number of construction processes: n=2

Number of construction sections: m = 4

Rhythm of flowing water: roof and wall plastering T 1 = 32/4 = 8d.

Paving stone T2 = 16/4 = 4d

Water layer section: k = 4 d

Number of construction teams: b 1= t 1/k=8/4=2 (unit)

B2= t2/k=4/4= 1 (pieces)

n？ =∑bj=2+ 1=3 (pieces)

Flow construction period: t = (m+n? - 1)×k =(4+3- 1)×4 = 24d