Traditional bicycle transmission rod structure

(1) according to the formula v=ωr, the angular velocity of the rear wheel is ω = VR = 3.3m/s33× 0.01m =10 rad/s;

(2) The angular velocity of the flywheel is the same as that of the rear wheel, which is10 rad/s;

Therefore, the linear speed of the flywheel is: v' = ω r =10 rad/s×1.2× 0.0825m = 0.21.25m/s;

The bicycle chain does not slip, and the linear velocity of the edge D of the toothed plate A is equal to the linear velocity of the flywheel edge, which is also 0.2125m/s;

Answer: (1) The angular velocity of the rear wheel C is 10 radian/second;

(2) The linear velocity of point D on the edge of tooth plate A is 0.21.25m/s. 。