Traditional Culture Encyclopedia - Traditional festivals - The dam section of the reservoir is trapezoidal, with a crest width of 5m, a slope of AD = 6 √ 2m, a dam height of 6m, and an oblique wave slope of BC I = 1: √ 3.
The dam section of the reservoir is trapezoidal, with a crest width of 5m, a slope of AD = 6 √ 2m, a dam height of 6m, and an oblique wave slope of BC I = 1: √ 3.
Solution: Let point C and point D be perpendicular to AB, and intersect AB at point E and point F respectively.
The slope of oblique wave BC is I = 1: √ 3, so CF/BF = Tanb = 1: √ 3, BF means the dam height is 6m, so BF = 6 √ 3m.
DE is also 6 meters high, DE is perpendicular to AB, and the slope AD=6√2 meters. In the right triangle ADE, AD is the hypotenuse, so AD? =AE？ +DE？ AE=6, and the triangle ADE is an isosceles right triangle.
DEFC is rectangular, EF=DC= dam crest width is 5m.
To sum up, the cardinal number AB = AE+EF+FB = 6+5+6 √ 3 = (11+6 √ 3) meters.
The inclination angle ∠A of the inclined plane AD is the acute angle of the isosceles right triangle ADE, so ∠ A = 45.
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